With the conclusion of NCERT Solutions Class 7 Maths Chapter 7: Congruence of Triangles, we have an advanced review, in a potential Exercise 7.7, which puts students to work solving an advanced, multi-step problem that requires them to use SSS, SAS, ASA, AAS, and RHS to prove triangles are congruent (or use congruence to prove a derived property). Experimentation with foreign geometric figures (not just triangles) such as parallelograms or figures with intersecting lines would occur in these problems.
The intention for this class is not to just prove triangles congruent, but to use triangles to prove a derived property—the specific one being to prove that the diagonals bisect each other or that a specific line segment is the perpendicular bisector of another segmented line. These final components of triangulation will be essential to prepare students for high school geometry.
Develop your problem-solving skills! Download the complete NCERT Solutions for Class 7 Maths Exercise 7.7 application in a precise, step-by-step process using the final application set. This resource will provide proofs and logical rationales to your complicated geometric problems.
Show that sides of a quadrilateral are parallel.
Show that a point is a midpoint or that an intersection is 90 degrees.
1. For each of the following angles, find another angle for which a triangle is (a) possible, (b) not possible. Find atleast two different angles for each category.
(i) 30∘
(ii) 70∘
(iii) 54∘
(iv) 144∘
Sol. We know that when the sum of two angles is less than 180∘ then the triangle exists and when the sum of two angles is greater than or equal to 180∘ then there exists no triangle.
(i) (a) Two possible angles are 70∘ and 60∘
(b) Two not possible angles are 150∘ and 155∘
(ii) (a) Two possible angles are 105∘ and 50∘
(b) Two not possible angles are 110∘ and 120∘
(iii) (a) Two possible angles are 120∘ and 110∘
(b) Two not possible angles are 126∘ and 130∘
(iv) (a) Two possible angles are 20∘ and 30∘
(b) Two not possible angles are 36∘ and 40∘
2. Determine which of the following pairs can be the angles of a triangle and which cannot.
(i) 35∘,150∘
(ii) 70∘,30∘
(iii) 90∘,85∘
(iv) 50∘,150∘
Sol. We know that if the sum of two angles of a triangle is greater than or equal to 180∘ then triangle is not possible with these angles.
(i) Given, the two angles of a triangle are 35∘ and 150∘.
Here, 35∘+150∘=185∘>180∘.
Therefore, triangle is not possible.
(ii) Given, the two angles of a triangle are 70∘ and 30∘.
Here, 70∘+30∘=100∘<180∘.
Therefore, triangle is possible.
(iii) Given, the two angles of a triangle are 90∘ and 85∘.
Here, 90∘+85∘=175∘<180∘.
Therefore, triangle is possible.
(iv) Given, the two angles of a triangle are 50∘ and 150∘.
Here, 50∘+150∘=200∘>180∘.
Therefore, triangle is not possible.
(Session 2026 - 27)