The NCERT Solutions Class 7 Maths Chapter 7: Congruence of Triangles wraps up by providing you with a last summary and application exercise called Exercise 7.5. This exercise will require you to provide a comprehensive understanding of all four congruence criteria: SSS, SAS, ASA and RHS.
The problems in this exercise could be application exercises, which will require you to systematically analyze geometric figures, select an appropriate criterion to prove congruence, and then make use of CPCT (corresponding parts of congruent triangles) to discover other properties or results. This will ensure you are confident in your application of these fundamental geometric tools in a variety of proof-writing situation.
Examine your understanding of all the congruence rules! Download the comprehensive, step-wise NCERT Solutions for Class 7 Maths Chapter 7 Exercise 7.5. This document is a great resource for your last chapter revision ahead of an exam.
SSS (Side-Side-Side)
SAS (Side-Angle-Side)
ASA (Angle-Side-Angle)/ AAS (Angle-Angle-Side)
RHS (Right angle - Hypotenuse - Side)
1. Construct triangles for the following measurements where the angle is included between the sides.
(i) 3 cm,75∘,7 cm
(ii) 6 cm,25∘,3 cm
(iii) 3 cm,120∘,8 cm
Sol. (i) 3 cm,75∘,7 cm
The steps of construction are given as
(a) Draw a line segment AB of length 7 cm using a ruler and a pencil.
(b) At point A , a draw an angle of 75∘ using protector and mark X .
(c) At point A , mark a point C along A X such that AC=3 cm.
(d) Join the point C to B . Then, △ABC is the required triangle.
(ii) 6 cm,25∘,3 cm
The steps of construction are given as
(a) Draw a line segment AB of length 3 cm using a ruler and a pencil.
(b) At point A , draw an angle of 25∘ using protector and mark X .
(c) At point A , mark a point C along A X such that AC=6 cm.
(d) Join the point C to B . Then, △ABC is the required triangle.
(iii) 3 cm,120∘,8 cm
The steps of construction are given as
(a) Draw a line segment AB of length 8 cm using a ruler and a pencil.
A↪8 cm⟶ B
(b) At point A , draw an angle of 120∘ using protector and mark X .
A120∘X cmB
(c) At point A , mark a point C along A X such that AC=3 cm.
(d) Join the point C to B . Then, △ABC is the required triangle.
(Session 2026 - 27)