The Cannizzaro reaction is a redox reaction in which two molecules of a non-enolizable aldehyde (i.e., an aldehyde without an α-hydrogen) undergo disproportionation in the presence of a strong base (like NaOH or KOH), producing:
Disproportionation = One molecule is oxidized, the other is reduced.
General Reaction:
2 RCHO + OH⁻ → RCOO⁻ + RCH2OH
Common examples of such aldehydes:
Alpha hydrogen (α-H) is the hydrogen atom attached to the α-carbon, i.e., the carbon adjacent to the carbonyl group (C=O).
If an aldehyde has an α-hydrogen, it can form an enolate and typically undergoes aldol condensation instead.
However, if no α-hydrogens are present, the Cannizzaro reaction takes place, as enolate formation is not possible.
The mechanism explains how two aldehyde molecules yield one alcohol and one acid. In 1853, Stanislao Cannizzaro obtained benzyl alcohol and potassium benzoate from benzaldehyde.
A hydroxide ion attacks the aldehyde carbonyl, forming a tetrahedral intermediate. This intermediate collapses, reforming the carbonyl and transferring a hydride ion to another aldehyde molecule. This results in one carboxylate ion and one alcohol ion, which receives a proton from the solvent. The acid product often requires post-treatment with acid to convert carboxylate to carboxylic acid. The reaction is third order overall: second order in aldehyde, first order in base.
Rate = k[RCHO]²[OH⁻]
At high base concentration, a second pathway becomes significant:
Rate = k[RCHO]²[OH⁻] + k’[RCHO]²[OH⁻]²
The second term involves the reaction of a divalent anion (RCHO²⁻) with another aldehyde. Deuterium labeling in D₂O confirms direct hydride transfer, as no deuterium appears at the alcohol’s alpha carbon.
Hydroxide ion (OH⁻) attacks the carbonyl carbon of one molecule of the aldehyde, forming a tetrahedral alkoxide intermediate.
The alkoxide ion formed donates a hydride ion (H⁻) to a second molecule of the aldehyde.
C₆H₅CHO + OH⁻ → C₆H₅CH₂OH + C₆H₅COO⁻
If KOH is used, the salt formed will be potassium benzoate (C₆H₅COOK).
When two different aldehydes without α-hydrogens are used in the reaction, it's called the Cross Cannizzaro Reaction.
In a typical Cannizzaro reaction, only 50% of the aldehyde is converted to alcohol and acid, making it inefficient. In the crossed Cannizzaro variant, a sacrificial aldehyde like formaldehyde is used as the reductant, increasing the yield of the desired alcohol from a more valuable aldehyde. Formaldehyde is oxidized to sodium formate while the target aldehyde is reduced to alcohol. This improves efficiency and product yield when dealing with non-enolizable aldehydes.
A common example:
Mixing formaldehyde and benzaldehyde in NaOH.
Industrially, the Crossed Cannizzaro reaction combined with aldol condensation helps produce valuable polyols.
(Session 2025 - 26)