The Cannizzaro reaction is a redox reaction in which two molecules of a non-enolizable aldehyde (i.e., an aldehyde without an α-hydrogen) undergo disproportionation in the presence of a strong base (like NaOH or KOH), producing:
Disproportionation = One molecule is oxidized, the other is reduced.
General Reaction:
2 RCHO + OH⁻ → RCOO⁻ + RCH2OH
Common examples of such aldehydes:
Alpha hydrogen (α-H) is the hydrogen atom attached to the α-carbon, i.e., the carbon adjacent to the carbonyl group (C=O).
If an aldehyde has an α-hydrogen, it can form an enolate and typically undergoes aldol condensation instead.
However, if no α-hydrogens are present, the Cannizzaro reaction takes place, as enolate formation is not possible.
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The mechanism explains how two aldehyde molecules yield one alcohol and one acid. In 1853, Stanislao Cannizzaro obtained benzyl alcohol and potassium benzoate from benzaldehyde.
A hydroxide ion attacks the aldehyde carbonyl, forming a tetrahedral intermediate. This intermediate collapses, reforming the carbonyl and transferring a hydride ion to another aldehyde molecule. This results in one carboxylate ion and one alcohol ion, which receives a proton from the solvent. The acid product often requires post-treatment with acid to convert carboxylate to carboxylic acid. The reaction is third order overall: second order in aldehyde, first order in base.
Rate = k[RCHO]²[OH⁻]
At high base concentration, a second pathway becomes significant:
Rate = k[RCHO]²[OH⁻] + k’[RCHO]²[OH⁻]²
The second term involves the reaction of a divalent anion (RCHO²⁻) with another aldehyde. Deuterium labeling in D₂O confirms direct hydride transfer, as no deuterium appears at the alcohol’s alpha carbon.
Hydroxide ion (OH⁻) attacks the carbonyl carbon of one molecule of the aldehyde, forming a tetrahedral alkoxide intermediate.
The alkoxide ion formed donates a hydride ion (H⁻) to a second molecule of the aldehyde.
C₆H₅CHO + OH⁻ → C₆H₅CH₂OH + C₆H₅COO⁻
If KOH is used, the salt formed will be potassium benzoate (C₆H₅COOK).
When two different aldehydes without α-hydrogens are used in the reaction, it's called the Cross Cannizzaro Reaction.
In a typical Cannizzaro reaction, only 50% of the aldehyde is converted to alcohol and acid, making it inefficient. In the crossed Cannizzaro variant, a sacrificial aldehyde like formaldehyde is used as the reductant, increasing the yield of the desired alcohol from a more valuable aldehyde. Formaldehyde is oxidized to sodium formate while the target aldehyde is reduced to alcohol. This improves efficiency and product yield when dealing with non-enolizable aldehydes.
A common example:
Mixing formaldehyde and benzaldehyde in NaOH.
Industrially, the Crossed Cannizzaro reaction combined with aldol condensation helps produce valuable polyols.
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(Session 2026 - 27)