Kinematics is the branch of physics that deals with the study of motion without considering the forces causing it.
Rest: If position does not change with time, then it is at rest; Motion: If the position of a particle changes with time, then it is called in motion.
A position vector specifies the location of a particle relative to a reference point, such as the origin. It is a vector that indicates the position of a specific point with respect to this reference. The direction of the position vector always points from the reference point (origin) toward the given point.
The shortest distance between the initial and final positions of the particle is called displacement
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Kinematics
Kinematics is the branch of physics that deals with the study of motion without considering the forces causing it. It focuses on describing the motion of objects through key concepts such as displacement, velocity, acceleration, and time. Kinematics helps us understand various types of motion, including linear, rotational, and projectile motion. It also explores concepts like position vectors, revolves, and motion under gravity. By analyzing these principles, kinematics provides a foundation for more complex studies in mechanics and physics.
1.0Basics of Kinematics
Rest: If position does not change with time, then it is at rest.
Motion: If the position of a particle changes with time, then it is called in motion.
Frame of Reference: A frame of reference is a perspective used to define the position or motion of a particle. Motion and rest are relative terms, dependent on the chosen frame of reference. Unless specified otherwise, the ground is typically considered the default reference frame.
Note: If a particle's position changes over time, it is in motion; if its position remains constant, it is at rest.
Type of Motion
Description
Examples
1-D Motion
Motion along a straight line, with position changing over time in one dimension.
Train on a straight track
2-D Motion
Motion in a plane, with position changing over time in two dimensions.
Earth revolves around the Sun
3-D Motion
Motion in space, with position changing over time in three dimensions.
Motion of an aeroplane
Position Vector: A position vector specifies the location of a particle relative to a reference point, such as the origin. It is a vector that indicates the position of a specific point with respect to this reference. The direction of the position vector always points from the reference point (origin) toward the given point.
The rate at which distance is covered with respect to time is called speed.
Scalar Quantity
Unit: SI→m/s
CGS Unit→cm/s
Conversion km/h→185m/s
Dimension:[M0L1T−1]
For a moving particle speed can never be zero or negative, it is always positive.
Types of Speed
Types of Speed
Description
Example
Uniform Speed
A particle covers equal distances in equal intervals of time.
Speed remains constant.
Example: A car moving at 20 meters every 5 seconds.
Non-uniform Speed
A particle covers unequal distances in equal intervals of time.
Speed varies over time.
Example: A car moves 20m in 5s, 40m in the next 5s, and 10m in another 5s.
Average Speed
The ratio of total distance traveled to the total time taken over a given time interval.
Average speed =Total DistanceTotal Time
Example: A car covers 60 meters in 5 seconds, average speed = 60m / 5s = 12 m/s.
Instantaneous Speed
The speed of a particle at a specific moment in time.
Speed at a particular instant.
Example: The speed of a car at the 10-second mark.
Uniform Speed
Non-uniform Speed (Variable Speed)
Cases of Average Speed
Case1. Particle moves with different uniform speeds in different time intervals its average speed over the total time of journey is given as
Vavg=nv1+v2+..........+vn
Case2. For Two equal intervals of time
Vavg=2v1+v2
Case3. Particle describes equal distances with different speeds then the average speed of particle over the total distance will be given as
S=nd
Vavg=v1+v22v1v2
4.0Velocity
The rate of change of position with time is called velocity.
It is a Vector Quantity.
Dimension : [M0L1T−1]
Unit: SI→m/s
CGS Unit→cm/s
Velocity can be positive, negative or Zero.
Types of Velocity
Type of Velocity
Description
Key Points
Uniform Velocity
The velocity remains constant in both magnitude and direction.
Occurs when a particle moves in a straight line without changing direction.
Non-uniform Velocity
The velocity changes in magnitude, direction, or both.
Occurs when either speed or direction, or both, vary during motion.
Average Velocity
The ratio of displacement to the total time taken by the body.
Average velocity=TimetakenNetDisplacement
Vavg=ΔtΔr=tf−tirf−ri
Its direction is along the displacement.
Note:
Time Average Velocity: Ifv=f(t)⇒<v>=∫t1t2dt∫t1t2vdt
Space Average Velocity If v=f(x)⇒<v>=∫x1x2dt∫x1x2vdt
Instantaneous Velocity: It is the velocity of a particle at a specific moment in time.
vavg=ΔtΔr
vinst=Δt→0lim(ΔtΔr)→vinst=dtdr
Change in velocity
Δv=vf−vi
If ∣vf∣=∣vi∣=v, then
∣Δv∣=2vsin(2θ)
where θ is the angle between initial and final velocity
5.0Acceleration
The rate of change of velocity is called acceleration.
It is a vector quantity.
Its direction is the same as that of change in velocity (not in the direction of the velocity).
Dimension : [M0L1T−2]
Unit: SI→m/s2
CGS Unit→cm/s2
There are 3 ways to change a velocity (vector)
Only magnitude change
Only direction change
Both direction+ magnitude change
Types of Acceleration
Type of Acceleration
Description
Key Points
Uniform Acceleration
Acceleration remains constant in both magnitude and direction during the motion of the particle.
The magnitude and direction of acceleration do not change.
Non-Uniform Acceleration
Acceleration changes in magnitude, direction, or both during the motion of the particle.
Either magnitude or direction, or both, of acceleration change.
Average Acceleration
The ratio of the total change in velocity to the total time taken by the particle.
aavg=ΔtΔv=tf−tivf−vi
Instantaneous Acceleration
Acceleration of a particle at a given instant is called instantaneous acceleration.
ainst=limΔt→0(ΔtΔv)⇒ainst=(dtdv) when v is function of time (t)
first derivative of velocity is called instantaneous acceleration
ainst=dtdv=dt2d2r
second derivative of position vector is called instantaneous acceleration
ainst=dtdv×dxdx⇒ainst=vdxdv when v is function of position (x)
Application of Calculus
For v-t relation⇒a=dtdv
For v-x relation ⇒a=vdxdv
Key Points
When a particle moves with constant velocity then its acceleration will be zero.
If particle moves with constant velocity then vavg=∣vavg∣=vinst=∣vinst∣
Acceleration which opposes the motion of the body is called retardation.
Increment or decrement in speed depends on direction of v and a
Case-1. If vanda are in the opposite direction then speed decreases.
Case-2. If vanda are in the same direction then speed increases.
6.0Velocity and Acceleration
Case-1. Angle between vanda is zero or they are parallel, speed increases.
Case-2. Angle between vanda is 90° or they are orthogonal, speed remains constant.
Case-3. Angle between vanda is 180° or they are anti-parallel, speed decreases
7.0Equations of Motion
a=dtdv
∫vudv=∫0tadt
v−u=at
v=u+at
v=dtds
∫0sds=∫0tvdt
s=ut+21at2
a=vdsdv
∫uvvdv=∫0sads
[2v2]uv=a[s]0s
v2=u2+2as
Note:
Displacement in nth second Snth=u+2a(2n−1)
s=Vavt=2(u+v)t
Galileo’s law of odd numbers: When particle starts from rest and moves with constant acceleration then ratio of distance travelled by it in successive equal intervals of time is
1:3:5:7........(2n–1)
Stopping Distance: The distance a vehicle travels after braking before it stops is called the stopping distance.
s=2a0u02 [since a is constant] s∝u02
if u becomes n times then s becomes n2 times that of previous value.
Stopping Time
t=a0u0 [since a is constant]⇒t∝u0
if u becomes n times then t becomes n times that of previous value.
Reaction Time: When a situation demands our immediate action, it takes some time before we really respond. Reaction time is the time a person takes to observe, think and act.
8.0Basic Graphs and Their Conversions
Position-Time graph
Tanθ=timedisplacement=velocity
Case-1
θ=0°
Tanθ=0°
velocity=0
The body is at rest.
Case-2
θ=constant
Tanθ=constant
velocity=constant
the body is in uniform motion
Case-3
θ>90°
Tanθ=negative
velocity=-ve but constant uniform motion
Case-4
θ is decreasing with time velocity is decreasing with time
Case-5
θ is increasing with time velocity is increasing with time
Area of x-t graph=∫xdt=No Physical Significance
Velocity-time graph
The slope of this graph represents acceleration.
Tanθ=timevelocity=acceleration
Area under v-t curve
∣displacement∣=A1−A2
Distance=A1+A2
Case-1
θ=0°
Tanθ=0°
acceleration=0
v=constant
uniform motion
Case-2
θ=constant
Tanθ=constant
acceleration=constant
uniformly accelerated motion
Case-3
θ>90°
Tanθ=negative
acceleration=−vebutconstant
uniform motion
Case-4
θ is decreasing with time tan is decreasing with time acceleration is decreasing with time acceleration goes on decreasing with time but it is not retardation
Case-5
θ is increasing with time acceleration is increasing with time
Acceleration-time graph
Area of a-t graph=∫adt=∫dv=v2−v1=change in velocity
Uniform or constant acceleration
Uniformly increasing acceleration.
a∝t0
Key Points
Following graphs do not exist in practice :
Case-1.
Explanation:
In practice, at any instant the body can not have two velocities or displacements or accelerations simultaneously.
Case-2.
Explanation:
Speed or distance can never be negative.
Case-3.
Explanation :
It is not possible to change any quantity without consuming time i.e. time can't be constant.
Graphical Problems in Horizontal Motion
If a car, starts from rest moves with constant acceleration for some time retards uniformly at rate and finally comes at rest total time of motion is T
vmax=(α+βαβ)T
S=21(α+βαβ)T2
9.0Motion Under Gravity
The acceleration a body experiences due to gravity is called acceleration due to gravity, denoted by g.
g=9.8m/s2 or g=980cm/s2 or g=32ft/s2
Sign Conventions
Note: Negative and positive signs are matters of our choice, so we can select any direction as positive and opposite side as negative.
Vertical Projection from ground
Equations of Motion:
u(initialvelocity)=+u
a(acceleration)=−g
at Time=t
Final Velocity=v
height above ground=h
v=u−gt
h=ut−21gt2
v2=u2−2gh
hnth=u−2g(2n−1)
Maximum Height (H)
H=2gu2
Total Time of Flight(T)
Time of Ascent (t1)=gu
Time of Descent(t2)=gu
Total TimeT=t1+t2=g2u
Motion under Gravity-Dropping from height
Body dropped from some height (initial velocity zero)
Equations of Motion:
u=0,a=+g, time=t, final velocity=v, height below dropping point=h
v=gt
h=21gt2
v2=2gh
Time to Reach Bottom T=g2H
Maximum speed at bottom v=2gH
Vertical Projection from Height
Case-1 : Downward Projection
Case- 2: Upward Projection
v=u+gt
h=ut+21gt2
v2=u2+2gh
hn=u+2g(2n−1)
vmax=u2+2gh
v=−u+gt
h=−ut+21gt2
v2=u2+2gh
hn=−u+2g(2n−1)
Hmax=H+2gu2
Distance travelled=H+gu2
Effect of Air Resistance
If ‘a’ is retardation due to air resistance,
For ascending motion(upward motion)
Time to go up, t1=g+a2h
Velocity of projection, v1=2(g+a)h
For descending motion (downward motion)
Time to go up, t1=g−a2h
Velocity on reaching ground, v1=2(g−a)h
Graphical Problems in Vertical Motion
A body is projected vertically upwards then
Graphs of displacement with respect to time
Graph of velocity with respect to time
Graph of acceleration with respect to time
A body dropped from some height
Graphs of displacement with respect to time
Graph of velocity with respect to time
Graph of acceleration with respect to time
10.0Motion In A Plane
2D Motion
When the motion of an object is restricted within a plane, it is said to undergo a motion in 2D.
2D motion can be studied as two independent 1D motions. (One along the x-axis and the other along the y-axis).
Example: Motion of a carrom coin, Projectile Motion, Circular Motion.
Projectile Motion: When a body moves with constant acceleration such that its initial velocity and acceleration are non- collinear then its path is parabola and motion is known as projectile motion.
Horizontal Motion
Vertical Motion
Initial velocity in horizontal direction
ux=ucosθ
Initial velocity in vertical direction uy=usinθ
Note: It is motion under the effect of gravity so that as particle moves upwards the magnitude of its vertical velocity decreases.
Case-1. If rain is dropping vertically with a velocity vR and an observer is gliding horizontally with speed vM then the velocity of rain relative to observer will be
vRM=vR−vM⇒vRM=−vRj^−vMi^
VRM=vR2+vM2
The direction of vRM is such that it makes an angle with the vertical given by
θ=tan−1(vRvM)
Case-2. If rain is already falling at an angle with the vertical with a velocity vR and an observer is gliding horizontally with speed vM finds that the rain drops are hitting on his head vertically downwards
vRM=vR−vM
vRM=(vRsinθ−vM)i^−vRcosθj^
Now for rain to appear falling vertically, the horizontal component of vRM should be zero,
(vRsinθ−vM)=0⇒sinθ=vRvM
VRM=VR2−VM2
13.0River-Boat (or Man) Problem
A man can swim with velocity v , i.e. it is the velocity of man w.r.t. still water.
If water is also flowing with velocity vR then velocity of man relative to ground vm=v+vR
If the swimming is in the direction of flow of water or along the downstream then
vm=v+vR
If the swimming is in the direction opposite to the flow of water or along the upstream then
vm=v−vR
If the man is crossing the river i.e. v and VR are non collinear then use vector algebra.
vm=v+vR
For shortest path
To reach at Bvsinθ=vR⇒Sinθ=vvR
so, time taken T=vcosθd=v2−vR2d
For minimum time
To cross the river in minimum time, the velocity along AB(vcosθ) should be maximum
Minimum Time =t=vd
BC=tminvR
Distance travelled along river flow = drift of man= tminvR=vdvR
14.0Sample Questions on Kinematics
Q-1.A river is 2 km broad and flows at 2 km/h. A boatman can row a boat at a speed of 6 km/h in still water. He rows 2 km upstream and then returns. What is the total time taken by the boatman to complete his journey?
Solution:
The velocity upstream is (4-2)km/hr and downstream is (4+2)km/hr
Total time taken=42+82=86=34hr=45 minutes
Q-2.A man is going east in a car with a velocity of 20 km/hr, a train appears to move towards north to him with a velocity of 203 km/hr. What is the actual velocity and direction of motion of the train?
Solution:
vTC=vT−vc
vT=vTC+vc=203j^+20i^
vT=(203)2+(20)2=1600=40kilometer/hour
tanθ=20203⇒θ=60∘
So, direction of motion of train is 60° N of E or E-60°-N
Q-3.Three boys A, B and C are situated at the vertices of an equilateral triangle of side d at t = 0. Each of the boys move with constant speed v. A always moves towards B, B towards C and C towards A. When and where will they meet each other?
Solution:
Due to symmetry, they will meet at the centroid of the triangle. Approaching velocity
of A and B towards each other is v + v cos 60° and they cover distance d when they meet.
So that time taken, is given by t=v+vcos60°d=v+2vd=3v2d
Q-4.Two particles A & B are projected from a building. A is projected with speed 2v making an angle 30° with horizontal & B with speed v making an angle 60° with horizontal. Which particle will hit the ground earlier?
Q-5.A ball is thrown from the ground to clear a wall that is 3 meters high and located 6 meters away. The ball lands 18 meters from the wall. What is the angle of projection of the ball?