The hybridization of NH₃ (ammonia) involves the combination of one nitrogen (N) atom's 2s orbital and three 2p orbitals to form four equivalent sp³ hybrid orbitals. This hybridization allows ammonia to form four sigma bonds with hydrogen atoms, resulting in its characteristic tetrahedral molecular geometry. Let’s discuss this in detail.
In detail, the hybridization of ammonia (NH₃) involves the combination of atomic orbitals on the nitrogen atom to form hybrid orbitals suitable for bonding with hydrogen atoms. Let's break down the process:
The molecular geometry of NH₃ is tetrahedral, with the nitrogen atom at the center and three hydrogen atoms surrounding it. The bond angle in between the hydrogen atoms is around 1070.
The molecular geometry of ammonia (NH₃) is trigonal pyramidal. The nitrogen atom is at the center, and three hydrogen atoms surround it. Since there is a lone pair on nitrogen, the molecule's shape deviates from the ideal tetrahedral angle.
Bond Angles: The ideal bond angle for a tetrahedral arrangement is 109.50. However, in ammonia, the bond angle is slightly less than this due to the lone pair's presence. The bond angle in NH₃ is approximately 1070.
(Session 2025 - 26)