Kohlrausch’s Law, formulated by Friedrich Kohlrausch in the late 19th century, explains how the limiting molar conductivity of an electrolyte at infinite dilution can be calculated by adding the individual contributions of its cation and anion.
This law is crucial in:
At infinite dilution, the limiting molar conductivity of an electrolyte is the sum of the limiting molar conductivities of its constituent ions.
Example
For sodium chloride (NaCl):
At infinite dilution, both ions move independently and contribute separately to the total conductivity.
Molar Conductivity
Molar conductivity (Λₘ) is a measure of how well an electrolyte conducts electricity in solution per mole of solute. It represents the conducting power of all the ions produced by one mole of the electrolyte in a given volume of solution.
Molar conductivity is defined as the conductivity (κ) of a solution divided by the molar concentration (c) of the electrolyte:
As the concentration of the solution decreases, molar conductivity increases. This is because:
At infinite dilution, where the electrolyte is completely dissociated and ion interactions are negligible, the molar conductivity reaches a maximum value known as the limiting molar conductivity, denoted by Λ⁰ₘ.
This value is crucial in:
Kohlrausch’s Law, also called the Law of Independent Migration of Ions, states that:
At infinite dilution, when the electrolyte is completely dissociated, the molar conductivity of an electrolyte is equal to the sum of the individual contributions of its cation and anion.
It can be mathematically expressed as:
Kohlrausch’s Law can be illustrated by plotting molar conductivity (Λₘ) of an electrolyte against the square root of its concentration (√c).
This graphical method is especially helpful in determining Λ⁰ₘ for weak electrolytes, as they do not fully dissociate even at low concentrations. Therefore, their limiting molar conductivity cannot be measured directly and must be extrapolated using data from strong electrolytes.
Hence, direct extrapolation for weak electrolytes is not reliable. Instead, Kohlrausch’s Law is used to compute Λ⁰ₘ indirectly.
For weak electrolytes, once Λ and Λ⁰ are known, the degree of dissociation (α) can be calculated using:
Where:
Kohlrausch’s Law has several important applications in electrochemistry, particularly in understanding the behavior of electrolytes in dilute solutions. Here are some of its key uses:
Kohlrausch’s Law helps determine the dissociation constant by using the degree of dissociation (α) and limiting molar conductivity (Λ⁰). This is crucial for analyzing the strength and ionization extent of weak acids and bases.
For weak electrolytes, direct measurement of limiting molar conductivity is not feasible. Using Kohlrausch’s Law, Λ⁰ can be calculated by summing the individual contributions of the ions at infinite dilution.
By comparing the molar conductivity (Λ) at a given concentration with Λ⁰, the degree of dissociation (α) can be calculated using the formula:
This helps quantify how much of the electrolyte has dissociated into ions in solution.
Kohlrausch’s Law is also useful for determining the solubility of salts like AgCl or BaSO₄. Once the limiting molar conductivity is known, the solubility can be back-calculated using conductivity data.
The law aids in calculating the transport number (or transference number) of ions—i.e., the fraction of total current carried by each ion in an electrolyte. This is vital in understanding current flow and ion movement in electrochemical cells.
Kohlrausch’s Law can be indirectly used to evaluate the ionic strength of a solution—a factor affecting activity coefficients and electrochemical equilibria.
1. Calculate the molar conductance of 0.02 M solution of an electrolyte which has a resistance of 310 ohm at 298 K. Cell constant is 0.68 cm-1.
Solution
To calculate the molar conductance (Λₘ) of a solution, we use the following steps
κ = Cell constant R
κ = 0.68t310 ==0.0021935 S cm−1
Rounding to a reasonable number of significant figures
The molar conductance of the solution is approximately 109.7 S cm² mol⁻¹
2.Determine the limiting molar conductivity of sodium sulfate (Na₂SO₄), given that the limiting molar conductivity of Na⁺ is 50.1 S·cm²/mol and that of ½ SO₄²⁻ is 80.0 S·cm²/mol.
Solution
Given:
Using Kohlrausch’s Law:
Answer:
(Session 2025 - 26)