Apollonius theorem is named after Apollonius of Perga, a Greek mathematician who has extensive applications in triangle problems and problems involving the medians of triangles. The Theorem is a seminal result in classical geometry that gives the relationship of triangle sides and the length of the median.
According to Apollonius's Theorem, the sum of squares of two sides is twice the square of a median, along with half the square of the third side. It describes the relationship between the sides and median of a triangle. "A median of a triangle is a line segment that connects a vertex of any triangle to the midpoint of the opposite side."
In brief, the Apollonius theorem statement is:
“The sum of the squares of any 2 sides of a triangle equals to twice the square on half the third side, together with twice the square on the median bisecting the third side.”
The formula for Apollonius's theorem is:
PQ2 + PR2 = 2PS2 + ½ QR2
Here,
Although the theorem can be proved using different methods, let us prove the Apollonius theorem with the help of Pythagoras theorem.
To Prove: PQ2 + PR2 = 2PS2 + ½ QR2
Given: In triangle PQR, PS is a median.
Construction: Construct PT perpendicular to QR.
Proof: PS is the median bisecting side of the QR
QS = SR = QR/2 ……………..(1)
Applying Pythagoras' theorem in triangles PTQ, PTR, and PTS we get,
In triangle PTQ,
PQ2 = QT2 + PT2 ……………..(A)
In triangle PTS,
PS2 = ST2 + PT2 ……………….(B)
In triangle PTR,
PR2 = RT2 + PT2 …………………(C)
Adding equation (A) and (C)
PQ2 + PR2 = QT2 + PT2 + RT2 + PT2
PQ2 + PR2 = QT2 + 2PT2 + RT2
By using equation (B)
PQ2 + PR2 = QT2 + 2(PS2 - ST2) + RT2
PQ2 + PR2 = 2PS2 + QT2 - 2ST2 + RT2
PQ2 + PR2 = 2PS2 + QT2 - ST2 + RT2 - ST2
PQ2 + PR2 = 2PS2 + (QT - ST)(QT +ST) + (RT - ST)(RT + ST)
Given in the figure that, RS = ST+RT, QS = QT - ST …….(D)
PQ2 + PR2 = 2PS2 + (QT + ST) QS + (RT - ST) RS
From equation 1
PQ2 + PR2 = 2PS2 + (QT - ST) (QR / 2) + (RT - ST) (QR/2)
PQ2 + PR2 = 2PS2 + (QT × QR) /2 + (ST × QR)/2 + (RT × QR)/2 - (ST × QR)/2
PQ2 + PR2 = 2PS2 + (QT × QR) /2 + (RT × QR)/2
PQ2 + PR2 = 2PS2 + (QR / 2) (QT + RT)
It is known that QT + RT = QR
PQ2 + PR2 = 2PS2 + (QR / 2) (QR)
PQ2 + PR2 = 2PS2 + (1/2) QR2
Hence Proved.
(Session 2025 - 26)