Linear graphs are a powerful tool in mathematics and everyday life, used to represent relationships between two variables that change at a constant rate. These graphs are essential in various fields, from economics to physics, helping us understand trends and predict outcomes. In this blog, we'll explore the definition, properties, and real-life applications of linear graphs with practical examples that highlight their importance.
A linear graph is a visual representation of a linear equation, typically in the form y = mx + b, where:
In simpler terms, a linear graph shows how one variable changes in relation to another in a straight-line pattern. The consistency in the slope means that the relationship between the two variables is constant, making linear graphs ideal for modeling proportional relationships.
Linear graphs have several important properties that make them easily recognizable and highly useful:
Linear graphs have numerous applications in everyday life. Let’s take a look at some of the examples of application of linear graphs in real life:
One of the most common applications of linear graphs is in business and economics, particularly in analyzing costs and revenues. For instance, if you run a business that has a fixed cost and a variable cost (like production costs), you can represent the total cost as a linear equation.
A linear graph would represent this equation, where the x-axis shows the number of units and the y-axis shows the total cost. The slope of the graph (10) indicates the increase in cost per unit, while the y-intercept (500) shows the fixed cost.
In physics, linear graphs are used to represent relationships between different physical quantities. A great example is the relationship between distance and time when an object is moving at a constant speed. The equation y = mx + b is commonly used to represent this relationship, where y is distance, x is time, and m is the speed of the object.
The graph of this equation will be a straight line with a slope of 60, meaning that for each hour, the car covers 60 kilometers. This graph can be useful for determining how long it will take the car to reach a certain distance or how far it will travel in a given time.
Another practical application of linear graphs is in the context of loan repayment. In this case, the total amount paid over time can often be represented by a linear equation, especially in scenarios with fixed monthly payments.
A linear graph can be used to visually track how the loan balance decreases over time, and the slope of the line would represent the rate of repayment.
Linear graphs can also be used in meteorology to model the change in temperature over time under certain constant conditions. For instance, if a city experiences a constant temperature change each day (say, it increases by 2°C every hour), this can be graphed as a linear function.
This linear relationship allows us to predict the temperature at any given hour, helping meteorologists plan weather forecasts.
In transportation, linear graphs are used to represent the relationship between speed and fuel consumption in vehicles. If a car uses fuel at a constant rate while traveling at a constant speed, this relationship can be graphed as a linear equation.
This allows drivers to estimate how much fuel will be used for a trip, which is useful for budgeting and route planning.
Example 1: Graph the equation y = 2x + 1.
Solution:
The equation y = 2x + 1 is in the form y = mx + b, where:
To graph this, we can follow these steps:
Example 2: From the graph, find the equation of the line that passes through the points (1, 4) and (3, 8).
Solution:
We are given two points, (1, 4) and (3, 8), and we need to find the equation of the line that passes through them.
The slope is calculated using the formula:
Substituting the points and
We can use the point (1, 4) and the slope m = 2 in the equation y = mx + b to find b.
Substituting y = 4, x = 1, and m = 2 into the equation:
Now that we have m = 2 and b = 2, the equation of the line is:
y = 2x + 2
Example 3: Solve for y when x = 5 in the equation y = -3x + 4.
Solution:
Substitute x = 5 into the equation y = –3x + 4:
y = –3(5) + 4 = –15 + 4 = –11
So, when x = 5, y = –11.
Question 1: Find the slope and y-intercept of the equation y = 5x - 7.
Question 2: Graph the equation y = –x + 3.
Question 3: Find the equation of the line that passes through the points (2, 5) and (4, 9).
Question 4: The equation of a line is given by y = 3x + 4. What is the value of y when x = 2?
Question 5: Solve for x in the equation 2x – 5y = 10 when y = 2.
(Session 2025 - 26)