A basic linear algebraic operation that is often utilized in computer science, engineering, and mathematics is the transpose of a matrix. It entails switching rows and columns by flipping a matrix across its diagonal. Beyond its computational importance, the transpose is essential for a variety of applications, from comprehending geometric transformations to solving linear equations. Let's now go over this idea in further detail, adding information on trigonometry and its uses, especially with regard to trigonometric functions and their significance in competitive tests like IIT-JEE.
By rearranging its rows into columns or columns into rows, a matrix can be transposed. A matrix is a rectangular array of numbers or functions organised into rows and columns. The transpose of a matrix is represented by the letter "T" in the superscript of the provided matrix. For example, if "A" is the provided matrix, the transposition is denoted by A' or AT.
The matrix transposition can be generalised as the following statement:
If A = [aij] m×n
then A′= [aij] n×m ..
Thus, the transpose of a matrix is described as "A matrix formed by turning all of the rows of a given matrix into columns and vice versa."
A matrix's transposition can be found by altering its rows and columns. Let's look at an example using a 2 x 3 matrix, which has three columns and two rows.
Consequently, the matrix transpose now contains three rows and two columns, making it a 3×2 matrix.
Trigonometry and matrices are often used in the same context, particularly in transformations and trigonometric problem-solving. While geometric and physical matrix applications necessitate trigonometric ratios and identities, rotation matrices employ trigonometric circular functions like sine and cosine.
Trigonometric functions are employed with matrices to depict rotations in two or three dimensions in any trigonometry IIT JEE Maths course pertaining to trigonometry. For example, a 2D rotation matrix is:
The transpose of a rotation matrix is equal to its inverse:
R (θ)T= R (−θ)
This property is vital in solving geometric problems in trigonometry.
Two matrices with the same order, A and B, will be used to illustrate the properties of the matrix transpose. A few characteristics of a matrix's transposition are listed below:
If the transpose of a matrix is transposed again, the result is the original matrix. For a matrix A:
(AT)T = A
This happens because any element aij in A becomes aj after the first transpose, and taking the transpose again converts it back to aij, restoring the original matrix.
The transpose of the sum of two given matrices is always equal to the sum of the transposes of the individual matrices. For matrices A and B:
(A+B)T = AT + BT
When a matrix is multiplied by a constant k and then transposed, the result is the same as the transpose of the matrix multiplied by k:
(kA)T = kAT
Here, k is a scalar constant.
The transpose of the product of two matrices is always equal to the product of their transposes taken in reverse order. For matrices A and B:
(AB)T= BTAT
These properties of matrix transposes are widely used in linear algebra to prove theorems and solve problems efficiently.
A symmetric matrix is a square matrix that is the same as its transpose, or A = AT. For every element in the matrix aij, it holds that aij = aji. Symmetric matrices are diagnosable by an orthogonal matrix and always have real eigenvalues. Mathematically, the symmetric matrix can be written as:
A = AT
A skew-symmetric matrix is a square matrix such that AT = –A, that is, for every element, aij = –aji. The diagonal elements of a skew-symmetric matrix are zero because aii = –aii. They are mathematically written as:
AT = –A
Problem 1: Given the matrix A
1 2 3
4 5 6
7 8 9
Calculate the transpose of A and determine if A is symmetric.
Solution: The transpose of a matrix A is obtained by swapping the rows and columns.
1 4 7
AT = 2 5 8
3 6 9
By comparing, we can see that matrix A AT. Hence, the matrix A is not symmetric.
Problem 2: Verify that (AB)T= BTAT for the given matrices:
1 2 3 9 8 7
A = 4 5 6 and B = 6 5 4
7 8 9 3 2 1
Solution: Let’s first calculate the Product of AB
calculate each element of the resulting matrix:
Row 1: (1)9+(2)6+(3)3=30, (1)8+(2)5+(3)2=24, (1)7+(2)4+(3)1=18
Row 2: (4)9+(5)6+(6)3=84, (4)8+5(5)+6(2)=69, 4(7)+5(4)6(1)=54
Row 3: 7(9)+8(6)+9(3)=138, 7(8)+8(5)+9(2)=114, 7(7)+8(4)+9(1)=90
The product of AB will be:
30 24 18
84 69 54
138 114 90
And the transpose of AB = ABT
30 84 138
24 69 114
18 54 90
Now similarly, calculate BT.AT
AT = 1 4 7
2 5 8
3 6 9
BT = 9 6 3
8 5 2
7 4 1
BT. AT = 30 84 138
24 69 114
18 54 90
Hence, AB)T = BT. AT
Problem 3: For a given Matrix D is:
1 2 3
4 5 6
7 8 9
Find the transpose of (DT)T
Solution:
DT = 1 4 7
2 5 8
3 6 9
Now, find Transpose of DT = (DT)T
(DT)T = 1 2 3
4 5 6
7 8 9
Thus, (DT)T = D, as mentioned in the above properties.
One of the most practical concepts taught in linear algebra is the transpose of a matrix, which has uses in geometry, trigonometry maths for JEE, and even more complex mathematics. Conjugate transposition and a few of its examples help students tackle a variety of problems including the most challenging trigonometry problems in IIT-JEE mathematics and other subjects. The gap between practical and theoretical mathematics is reduced.
(Session 2025 - 26)