The I3− molecule is known as a triiodide ion. It is an anion composed of three iodine atoms with a negative charge.
Hybridization of I3− ion involves the iodine atoms, which exhibit a form of hybridization that leads to the linear molecular structure of the ion. Hybridization is a concept in molecular orbital theory that explains the mixing of atomic orbitals to form new, hybrid orbitals that are suitable for bonding in a molecule. In the case of I3−, the iodine atoms utilize a type of Hybridization of I3− ion known as sp3d hybridization.
In this section, we will discuss the hybridization of I3 and how to find the hybridization of I3 along with its important characteristics.
Let’s discuss the hybridization for I3− Atomic Orbitals in detail :
Each iodine atom in I3− contributes one of its 5p orbitals to form a set of three sp3d hybrid orbitals. These hybrid orbitals are involved in the sigma (σ) bonds, which are the single covalent bonds between the iodine atoms.
Formation of Sigma Bonds: The three iodine atoms are linked by sigma (σ) bonds and the molecular orbitals formed by the overlap of these hybrid orbitals contribute to the linear structure of the triiodide ion.
Delocalized Electrons: The negative charge (−1) in the triiodide ion is associated with the presence of an extra electron, resulting in a more delocalized electron cloud across the molecule.
Hybridization of central iodine atom in I3−
If the molecular structure of I3− involves three equatorial lone pairs on the central iodine atom and the terminal iodines are bonded axially in a linear shape, this would lead to a trigonal bipyramidal arrangement. In trigonal bipyramidal geometry, the hybridization of I in I3 would be sp3d.
Let’s see what kind of chemical bonding involves in triiodide (I3− )-
The triiodide ion, I3−, is formed by the combination of three iodine atoms. The bonding in I3− involves covalent bonds between the iodine atoms. Here's a more detailed explanation :
(Session 2025 - 26)