`int[sin^2((9pi)/8+x/4)-sin^2((7pi)/8+x/4)]dx`

int[sin^(2)((9 pi)/(8)+(x)/(4))-sin^(2)((7 pi)/(8)+(x)/(4))]dx

The value of sin^2 (pi/8)+sin^2 ((3pi)/8)+sin^2 ((5pi)/8)+sin^2 ((7pi)/8) is

sin^4(pi/8)+sin^4((2pi)/8)+sin^4((3pi)/8)+sin^4((4pi)/8)+sin^4((5pi)/8)+sin^4((6pi)/8)+sin^4((7pi)/8)=

Prove that: sin^4(pi/8)+sin^4((3pi)/8)+sin^4((5pi)/8)+sin^4((7pi)/8)=3/2

sin^(2)((pi)/(8))+sin^(2)((3pi)/(8))+sin^(2)((5pi)/(8))+sin^(2)((7pi)/(8))= .........

Prove that: sin^2(pi/(18))+sin^2(pi/9)+sin^2((7pi)/(18))+sin^2((4pi)/9)=2

Show that sin ^(4). (pi)/(8)+ sin ^(4) .(3pi)/(8) sin ^(4). (5pi)/(8)+sin ^(4). (7pi)/(8) =(3)/(2)

Prove that: sin^4((pi)/8)+sin^4((3pi)/8)+sin^4((5pi)/8)+sin^4((7pi)/8)=3/2

Statement I : sin^2pi/8+sin^2(3pi)/8+sin^2(5pi)/8+sin^2(7pi)/8=2 Statement II sin^4pi/8+sin^4 (3pi)/8+sin^4(5pi)/8sin^4(7pi)/8=3/2