A particle of mass m is made to move with unifrom speed v along the perimeter of a regular hexagon. Magnitude of impulse applied at each corner of the heaxogen is

A particle of mass is made to move with uniform speed v along the perimeter of a regular polygon of 2n sides. The magnitude of impulse of impulse applied at each corner of the polygon in amv sin pi//bn . Then a/b =

A particle of mass m is made to move with uniform speed u along the perimeter of a regular polygon of n sides. What is the magnitude of impulse applied by the particle at each corner of the polygon?

A particle of mass m is made to move with uniform speed u along the perimeter of a regular polygon of n sides. What is the magnitude of impulse applied by the particle at each corner of the polygon?

A particle of mass in is made to move with uniform speed v_0 along the perimeter of a regular hexagon, inscribed in a circle of radius R . The magnitude of impulse applied at each corner of the hexagon is

A particle of mass in is made to move with uniform speed v_0 along the perimeter of a regular hexagon, inscribed in a circle of radius R . The magnitude of impulse applied at each corner of the hexagon is

A particle of mass m is made to move with uniform speed v_(0) along the perimerter of a regular hexagon. Inscribed in a circle of radius. R. The magnitude of impulse applied at each corner of the hexagon is :-

A particle of mass m is made to move with uniform speed v_(0) along the perimerter of a regular hexagon. Inscribed in a circle of radius. R. The magnitude of impulse applied at each corner of the hexagon is :-

A particle of mass m is made to move with a uniform speed "v' along the perimeter of a polygon of n sides inscribed in a circle of radius "a".

The perimeter of a regular hexagon with each side measuring 8m

Find the perimeter of a regular hexagon with each side measuring 8 m.