`int[(cot^2 2x-1)/(2cot2x)-cos8xcot4x]dx`

int cot^2 x dx

int(cos8x-1)/(tan2x-cot2x)dx

int(cos8x-1)/(tan2x-cot2x)dx

int(cot^2x-cosec^2x)/x^2dx

int cot^(2)x dx=

int(cot^(2)x+cot^(4)x)dx=

If Integration using trigonometric identities : int(cos 8x+1)/(tan2x-cot 2x)dx=acos 8 x+c then a = ..........

cotxcot2x-cot2xcot3x-cot3xcotx=1

cotxcot2x-cot2xcot3x-cot3xcotx=1

int cot ^(2)x dx=