The new equation of the curve `4(x-2y+1)^2+9(2x+y+2)^2 =25`, if the lines `2x+y+2=0 and x-2y+1 = 0` are taken as the new x and y axes respectively is

The changed equation of locus x^(2)+6xy+y^(2)=1 when the lines x+y=0 and x-y+1=0 are taken as the new x and y axis respectively is given by

If the two lines of regression are 2x-y-4=0 and 9x-2y-38=0 , then the means of x and y variates respectively are

The equation of the image of the curve x^(2)-y^(2)=4 with respect to the line x+y-2=0, is

If the equations 2x+3y+1=0,2x+y-1=0 and ax+2y-b=0 are consistent, then

A curve satisfies the differential equation (dy)/(dx)=(x+1-xy^2)/(x^2y-y) and passes through (0,0) (1) The equation of the curve is x^2+y^2+2x=x^2y^2 (2) The equation of the curve is x^2+y^2+2x+2y=x^2y^2 (3) x=0 is a tangent to curve (4) y=0 is a tangent to curve

For the circle x^(2)+y^(2)-2x-4y-4=0 ,the lines 2x+3y-1=0,2x+y-1=0 are

Find the equation of the tangent to the curve y=x^2-2x+1 which is parallel to the line 2x-y+9=0 .

Find the equation of the tangent to the curve (X^2)/(a^2) + (y^2)/(b^2) = 1 at (x_0.y_0)

The equation of the line that touches the curves y=x|x| and x^2+(y-2)^2=4 , where x!=0, is:

The equation of the line that touches the curves y=x|x| and x^2+(y-2)^2=4 , where x!=0, is: