The refractive index of a prism with apex angle `A` is `cot A//2`. Prove that the angle of minimum deviation is `delta_m = (180^@ - 2 A)`.

The refracting angle of a prism is A and the refractive index of its material is cot A//2 .For a ray of light incident on the prism,find the angle of minimum deviation in terms of A.

The refracting angle of a prism is A and refractive index of material of prism is cot (A)/(2) . The angle of minimum deviation is

The refractive index of the material of prism sqrt3, then the angle of minimum deviation of prism is