Home
Class 12
PHYSICS
An AC source is connected to the LC seri...

An AC source is connected to the LC series circuit with `V = 10 sin (314t)`. Find the current in the circuit as function of time ? (`L = 40 mH, C = 100 mu F`)

Promotional Banner

Similar Questions

Explore conceptually related problems

A circuit consisting of a capacitor with capacitance C and a resistance R connected in series was connected at the moment t=0 to a source of ac voltage V=V_(m) cos omegat . Find the current in the circuit as a function of time t .

An a.c. source is connected across an LCR series circuit with L = 100 mH, C = 0.1muF and R = 50 Omega . The frequency of ac to make the power factor of the circuit, unity is

An a.c. source is connected across an LCR series circuit with L = 100 mH, C = 0.1muF and R = 50 Omega . The frequency of ac to make the power factor of the circuit, unity is

A series LCR circuit has R=5 Omega, L=40 mH and C=1mu F , the bandwidth of the circuit is

A series LCR circuit has R=5 Omega, L=40 mH and C=1mu F , the bandwidth of the circuit is

In an LC circuit shown in figure, if the switch is closed at t = 0 , find the equation for instantaneous current in Q_("max")=100 mu C, L=40 mH, C = 100 mu F

An LCR series circuit with L = 100 mH, C = 100 muF, R = 120 Omega is connected to an AC source of emf epsilon = (30 V) sin (100s^(-1))t . Find the impedane, the peak current and the resonant frequency of the circuit.

An LCR series circuit with L = 100 mH, C = 100 muF, R = 120 Omega is connected to an AC source of emf epsilon = (30 V) sin (100s^(-1))t . Find the impedane, the peak current and the resonant frequency of the circuit.

An LCR series circuit with L = 100 mH, C = 100 muF, R = 120 Omega is connected to an AC source of emf epsilon = (30 V) sin (100s^(-1))t . Find the impedane, the peak current and the resonant frequency of the circuit.

A 25 (mu)F capacitor, a0.1 H inductor and a 25 Omega resistorare connected in series with an ac source of emf E=310 sin 314 t. Find the current in the circuit.