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(Sec theta - tan theta)/(Sec theta + tan...

`(Sec theta - tan theta)/(Sec theta + tan theta) = cos^2 ( pi/4 + theta / 2)`

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`(sectheta -tantheta)/(sectheta+tantheta) = cos^2(pi/4+theta/2) `
As `cos2theta = 2cos^2theta -1, cos^2theta = (1+cos2theta)/2)`
So, our equation becomes,
`=>(1-sintheta)/(1+sin theta) = (1+cos(pi/2+theta))/2`
`=>(1-sintheta)/(1+sin theta) = (1-sintheta)/2`
`:. 1+sin theta = 2=> sin theta = 1`
`=>theta = (2npi+pi/2)`
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