A He atom at 300 K is released from the surface of the earth to travel upwards. Assuming that it undergoes no collision with other molecules, how high will it be before coming to the rest?

If nitrogen gas molecule goes straight up with its rms speed at 0^@ C from the surface of the earth and there are no collisions with other molecules, then it will rise to an approximate height of.

If nitrogen gas molecule goes straight up with its rms speed at 0^@ C from the surface of the earth and there are no collisions with other molecules, then it will rise to an approximate height of.

A nitrogen molecule at the surface of earth happens to have 'rms' speed for that gas at 0^(@)C . If it were to go straight up without colliding with other molecules, how high would it rise? (Mass of nitrogen molecule, m=4.65xx10^(-26) kg,R=8.3J//mol//K )

The velocity of a nitrogen molecule on the earth surface is equal to its rms speed at 0^@C IF the molecule moves straights upwards without any collisions with other molecules, determine the height up to which the molecule would rise. The mass of a nitrogen molecule m=4.65 times 10^-26 kg and k=1.38 times 10^-23 J.K^-1

A smooth tunnel is dug along the radius of the earth that ends at the centre. A ball is released from the surface of earth along the tunnel. If the coefficient of restitution is 0.2 between the surface and ball, then the distance travelled by the ball before second collision at the centre is

A particle is given a velocity (v_(e ))/(sqrt(3)) in a vertically upward direction from the surface of the earth, where v_(e ) is the escape velocity from the surface of the earth. Let the radius of the earth be R. The height of the particle above the surface of the earth at the instant it comes to rest is :