The EMF generated across a thermocouple with cold junction at `0^(@)C` , is
`E=a theta+btheta^(2)`
with a `=30muV(.^(@)C)^(-1)` and `b=0.08muV(.^(@)C)^(-2)`
At E=6mV. The hot junction temperature is about

For a certain thermocouple , varepsilon=alphatheta+(1)/(2)betatheta^(@),where theta.^(@)C is the temperature of the hot junction and 0^(@)C is the temperature of the cold junction . If alpha =10 mu V.^(@)C^(-1) and beta=-(1)/(20)muV.^(@)C^(-2) , find the neutral temperature and temperature of inversion.

Write down the equation for thermo emf when cold junction is at 0^@C and the hot junction is at T^@C .

The e.m.f of a thermocouple one junction of which is kept at 0^@C , is given by e=at+bt^2 The neutral temperatue will be

For a copper-iron and a chromel-alumel thermocouple, the plots between thermoelectric emf and the temperature theta of the hot junction (when the cold junction is at 0^(@)C )are found to satisfy approximately the parabola equation V=alpha theta+(1)/(2)betatheta^(2) with alpha=14muV^(@)C^(-1) beta=-0.04V^(@)C^(-2) (copper-iron) alpha=41muCV^(@)C^(-1),beta=-0.002V^(@)C^(-2) (chromel-alumel) Which of the two thermocouples would you use to measure temperature in the range of a about 500^(@)C to 600^(@)C ?

For a copper-iron and a chromel-alumel thermocouple, the plots between thermoelectric emf and the temperature theta of the hot junction (when the cold junction is at 0^(@)C )are found to satisfy approximately the parabola equation V=alpha theta+(1)/(2)betatheta^(2) with alpha=14muV^(@)C^(-1) beta=-0.04V^(@)C^(-2) (copper-iron) alpha=41muCV^(@)C^(-1),beta=-0.002V^(@)C^(-2) (chromel-alumel) Which of the two thermocouples would you use to measure temperature in the range of a about 500^(@)C to 600^(@)C ?

For a copper-iron and a chromel-alumel thermocouple, the plots between thermoelectric emf and the temperature theta of the hot junction (when the cold junction is at 0^(@)C )are found to satisfy approximately the parabola equation V=alpha theta+(1)/(2)betatheta^(2) with alpha=14muV^(@)C^(-1) beta=-0.04V^(@)C^(-2) (copper-iron) alpha=41muCV^(@)C^(-1),beta=-0.002V^(@)C^(-2) (chromel-alumel) Which of the two thermocouples would you use to measure temperature in the range of a about 500^(@)C to 600^(@)C ?

The thermo emf of a copper-constantan thermocouple with one junction at 0^(@)C and the other at t^(@)C is given by the relation varepsilon=at=(1)/(2)bt^(2) where varepsilon is in muV, a=41 mu V.^(@)C^(-2) . If the thermo emf developed is 5.5 mV, find the temperature of the hot junction.