Let E be the energy required to raise a satellite to height `h` above earth's surface and E' be the energy required to put the same satellite into orbit at that height. Then `E//E'` is equal to

The ratio of energy required to raise a satellite to a height h above the earth surface to that required to put it into the orbit is

The ratio of energy required to raise a satellite to a height h above the earth surface to that required to put it into the orbit is

The ratio of energy required to raise a satellite to a height h above the earth surface to that required to put it into the orbit is

The ratio of the energy required to raise a satellite upto a height h above the surface of earth to that the kinetic energy of the satellite into the orbit there is (R=radius of earth)

At what height above Earth's surface is the energy required to lift a satellite to that height equal to the kinetic energy required for the satellite to be in orbit at that height ?(b) For greater heights, which is greater, the energy for lifting or the kinetic energy for orbiting ?

The energy required to take a satellite to a height ‘h’ above Earth surface (radius of Earth =6.4xx10^3 km ) is E_1 and kinetic energy required for the satellite to be in a circular orbit at this height is E_2 . The value of h for which E_1 and E_2 are equal, is:

The energy required to take a satellite to a height ‘h’ above Earth surface (radius of Earth =6.4xx10^3 km ) is E_1 and kinetic energy required for the satellite to be in a circular orbit at this height is E_2 . The value of h for which E_1 and E_2 are equal, is:

The energy required to take a satelite to a height h above Earth surface (radius of Earth =6.4xx10^(3) km) is E_(1) and kinetic energy required for the satellite to be in a circular orbit at this height is E_(2) . The value of h (in km) for which E_(1) and E_(2) are equal is