A plane parallel to the base cuts the altitude of the cone in two equal parts. Find the ratio of the volumes of the two parts.

The height of a cone is 10cm. The cone is divided into two parts using a plane parallel to its base at the middle of its height.Find the ratio of the volumes of the two parts.

A plane parallel to the base of a cone cuts its axis in the ratio 2:1 from its base. The ratio of the volume of the lower part of the cone to that of the upper part is

The height of a right circular cone is 30 cm . A small part of the cone is cut off from the above part of the cone with the help of a plane parallel to the base of the cone. If the volume of the small part be (1)/(27) part of the volume of the original cone , then at what distance above the base of the cone , it has been cut off ?

A cone of radius 8cm and height 12cm is divided into two parts by a plane through the mid-point of its axis parallel to its base. Find the ratio of the volumes of the two parts.

Two parallel planes which are parallel to the base of a right circular, cone cut the height of the cone are equally. Show that the ratio of the volume of three parts of the cone is 1:17:19.

A cone of radius r сm and height h cm is divided into two parts by drawing a plane through the middle point of its height and parallel to the base. What is the ratio of the volume of the original cone to the volume of the smaller cone?

A cone of radius r сm and height h cm is divided into two parts by drawing a plane through the middle point of its height and parallel to the base. What is the ratio of the volume of the original cone to the volume of the smaller cone?

The slant height of a right circular cone is 10 cm and its height is 8 cm. It is cut by a plane parallel to its base passing through the midpoint of the height. Ratio of the volume of the cone to that of the frustum of the cone cut is