The area of a trapezium is half the product of its height and sum of parallel sides.

The area of a trapezium is half the product of its height and the sum of parallel sides.GIVEN : A trapezium ABCD in which AB|CD;AB=a,DC=b and AL=CM=h, where AL perp DC and CM perp AB. TO PROVE : ar (trap.ABCD)=(1)/(2)HX(A+B) construction : Join AC^(2)

The symbolic form of "area (A) of a trapezium is half of the product of distance between the paralel side (h) and sum of the lengths of parallel sides (a,b)" is____.

The ratio of the length of the parallel sides of a trapezium is 3:2. The shortest distance between them is 20 cm. If the area of the trapezium is 550 cm^2, the sum of the lengths of the parallel sides is-

The area of a trapezium is 91cm^(2) and its height is 7cm. If one of the parallel sides is longer than the other by 8cm, find the two parallel sides.

The area of a trapezium is 216 m^(2) and its height is 12m. If one of the parallel sides is 14 m less than the other, find the length of each of the parallel sides.

The area of a triangle is half the product of any of its sides and the corresponding altitude.

The area of a trapezium is 105 meter^2 and the lengts of its parallel sides are 9 m and 12 m respectively . Then the height of the trapezium is