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A particle starts sliding down a fricti...

A particle starts sliding down a frictionless inclined plane. If ` S_(n) ` is the distance travelled by it from time ` t = n-1 sec `, to `t = n sec`, the ratio ` (S_(n))/(s_(n+1))` is

A

`(2n -1)/(2n+1)`

B

`(2n +1)/(2n)`

C

`(2n )/(2n+1)`

D

`(2n +1)/(2n-1)`

Text Solution

Verified by Experts

The correct Answer is:
A

` s_(n) = (a)/(2)(2n-1)`,
`s_(n+1) = (a)/(2) [2(n+1)-1] = (a)/(2) (2n +1)`
` (s_(n))/(s_(n+1)) = (2n-1)/(2n+1)`
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