A car accelerates from rest at a constant rate `alpha` for some time, after which it decelerates at a constant rate `beta,` to come to rest. If the total time elapsed is t seconds. Then evalute (a) the maximum velocity reached and (b) the total distance travelled.

Answer

A, B

Explanation

`Distance travelled = area of Delta ABC`
` = 1//2 xx base xx altitude = 1/2 xx t xx v_(max) `
`= 1/2 xx t xx (alpha beta)/( alpha+ beta)t = 1/2 ((alpha beta)/(alpha + beta)) t^(2)`