A ball is released from the top of a tower of height h metre. It takes T second to reach the ground. What is the position of the ball in `T/3` second?

Options

A. `( 8 h)/(9)` meters from the ground
B. `( 7 h)/(9)` meters from the ground
C. `( h)/(9)` meters from the ground
D. `( 17 h)/(18)` meters from the ground

Answer

A

Explanation

We know that `s = ut + 1/2 gt^(2) , or h = 1/2 gT^(2)` `(:. U = 0)`
now for `T//3` second , vertical distance moved is given by
` h' = 1/2 g (( T)/3)^(2) rArr h' = 1/2xx(gT^(2))/9 = h/9 `
`:.` Position of ball from ground `= h - (h)/(9) = (8h)/(9)`