For a particle in uniform circular motion , the acceleration ` vec(a)` at a point ` p ( R, theta )` on the circle of radiu ` R` is ( Here ` theta` is measured from the ` x- axis` )

Options

A. `-(v^(2))/(R ) cos theta hat(i) + (v^(2))/(R ) sin theta hat(j)`
B. `-(v^(2))/(R ) sin theta hat(i) + (v^(2))/(R ) cos theta hat(j)`
C. `-(v^(2))/(R ) cos theta hat(i) - (v^(2))/(R ) sin theta hat(j)`
D. `-(v^(2))/(R ) hat(i) + (v^(2))/(R ) hat(j)`

Answer

C

Explanation

Clearly ` vec(a) = a_(c) cos theta (-hat(i)) + a_(c) sin theta (-hat(j))`
` = (-v^(2) )/(R )cos theta hat(i) - (v^(2))/ (R) sin theta hat ( j) `