A boy can throw a stone up to a maximum height of 10 m. The maximum horizontal distance that the boy can throw the same stone up to will be:

Options

A. `20 sqrt(2) m`
B. `10 m`
C. `10 sqrt(2) m`
D. `20 m`

Answer

D

Explanation

` R = (u^(2) sin 2 theta )/ ((g)) rArr R _(max) = (u^(2))/(g) `
` R _(max) = (10 xx g xx 2)/ (g) = 20 meter `