A block of mass 1 kg lies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is `5m//s^2`, the frictional force acting on the block is…………newtons.

Explanation

To solve the problem, we need to determine the frictional force acting on a block of mass 1 kg that is placed on a horizontal surface in a truck that is accelerating at \(5 \, \text{m/s}^2\). The coefficient of static friction between the block and the surface is \(0.6\).

### Step-by-Step Solution:

1. **Identify the Forces Acting on the Block:**
- The weight of the block (\(W\)) acting downwards:
\[
W = mg = 1 \, \text{kg} \times 10 \, \text{m/s}^2 = 10 \, \text{N}
...