A ship of mass `3xx10^7kg` initially at rest, is pulled by a force of `5xx10^5N` through a distance of 3m. Assuming that the resistance due to water is negligible, the speed of the ship is

Options

A. `1.5m//sec`
B. `60m//sec`
C. `0.1m//sec`
D. `5m//sec`

Answer

C

Explanation

`F=ma`
`implies a=F/m=(5xx10^4)/(3xx10^7)=5/3xx10^-3ms^-2`
Also, `v^2-u^2=2as`
`impliesv^2-0^2=2xx5/3xx10^-3xx3=10^2`
`impliesv=0.1ms^-1`