A uniform rope of length L , resting on frictionless horizontal table is pulled at one end by a force F . What is the tension in the rope at a distance x from the end where the force is applied ?
[ Hint : Consider the motion of the entire rope and the motion of x length of rope using P = ma formula and third law of motion ]

Answer

A

Explanation

From equation (i) `T=M/L(L-l)a`
Also, `F=Ma` `:.` `T/F=((L-l)/(L))impliesT=F(1-l/L)`