A block is kept on a frictionless inclined surface with angle of inclination `alpha`. The incline is given an acceleration 'a' to keep the block stationary. Then a is equal to

Options

A. (a) `g cosec alpha`
B. (b) `g//tan alpha`
C. (c) `g tan alpha`
D. (d) g

Answer

C

Explanation

From diagram,

For block to remain stationary,
`mg sin alpha=ma cos alphaimpliesa = g tan alpha`