The numerical value of the angular velocity of rotation of the earth should be…….. Rad/s in order to make the effective acceleration due to gravity equal to zero.

Answer

A, B, C, D

Explanation

We know that g' = g - Romega^2 cos^2 phi`
At equator, `phi = 0, Therefore g' =g- Romega^2`
Here `g' = 0 :. =sqrt((g)/(R ) = 1.23xx10^(-3) rad//s`