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The numerical value of the angular veloc...

The numerical value of the angular velocity of rotation of the earth should be…….. Rad/s in order to make the effective acceleration due to gravity equal to zero.

Text Solution

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The correct Answer is:
A, B, C, D
We know that g' = g - Romega^2 cos^2 phi`
At equator, `phi = 0, Therefore g' =g- Romega^2`
Here `g' = 0 :. =sqrt((g)/(R ) = 1.23xx10^(-3) rad//s`
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Knowledge Check

  • The value of acceleration due to gravity of earth :

    A
    is the same on equator and poles
    B
    is the least on poles
    C
    is the least on equator
    D
    increase from pole to equator

  • The value of acceleration due to gravity of the earth is

    A
    `98 m//s^2`
    B
    `9.8 m//s^2`
    C
    `0.98 m//s^2`
    D
    `0.098 m//s^2`

  • In order to make the effective acceleration due to gravity at the equator to zero, the numerical value of the angular velocity of rotation of the earth should be [Radius of the earth=6400 km, g=10m/s^(2) ]

    A
    `(1)/(400)` rad/s
    B
    `(1)/(200)` rad/s
    C
    `(1)/(800)` rad/s
    D
    `(1)/(500)` rad/s

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