A body is projected vartically upwards from the bottom of a crater of moon of depth `( R)/(100)` where R is the radius of moon with a velocity equal to the escape velocity on the surface of moon. Calculate maximum height attained by the body formt eh surface of the moon.

Explanation

Total energy at A = Total energy at B
(K.E)_A + (P.E)_A = (P.E)_B`
`rArr (1)/(2)mxx(2GM)/(R ) +[(-GMm)/(2R^3){(3R^2 - (99R)/(100)^2}] = -(GMm)/(R+h_`
On solving we get `h = 99.5R.`