A particle executes simple harmonic motion between `x = -A and x = + A`. The time taken for it to go from `0 to A//2 is T_1 and to go from A//2 to (A) is (T_2)`. Then.

Options

A. `T_1 lt T_2`
B. `T_1 gt T_2`
C. `T_1 = T_2`
D. `T_1 = 2 T_2`

Answer

A

Explanation

The velocity of a body executing (S.H.M.) is maximum at its centre and decreases as the body proceeds to the extremes. Therefore if the taken for the body to go from `O to A//2` is (T_1) and to go from `A//2 to A` is (T_2) then obviously.
`T_1 lt T_2`.