A linear harmonic oscillator of force constant `2 xx 10^6 N//m` and amplitude (0.01 m) has a total mechanical energy of (160 J). Its.

Options

A. maximum potential energy is (100 J)
B. maximum kinetic energy is (100 J)
C. maximum potential energy is (160 J)
D. maximum potential energy is zero.

Answer

B, C

Explanation

The total energy of the oscillator
`=(1)/(2) kA^2 = Max.K.E.`
`= (1)/(2) xx 2 xx 10^6 xx (0.01)^2 = 100 J`
As total mechanical energy = (160 J)
The (P.E.) at equilibrium position is not zero.
(P.E.) at mean position = `(160 - 100) J = 60 J`
:. Max (P.E.) = `(100 + 60) J = 160 J`.
(##JMA_CHMO_C10_014_S01##).