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If a spring has time period T, and is cu...

If a spring has time period T, and is cut into n equal parts, then the time period of each part will be.

A

`Tsqrtn`

B

`T//sqrtn`

C

`nT`

D

`T`

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The correct Answer is:
To solve the problem, let's break it down step by step: ### Step 1: Understand the Time Period of a Spring The time period \( T \) of a spring in simple harmonic motion is given by the formula: \[ T = 2\pi \sqrt{\frac{m}{k}} \] where: - \( m \) is the mass attached to the spring, - \( k \) is the spring constant. ### Step 2: Consider the Effect of Cutting the Spring When the spring is cut into \( n \) equal parts, each part will have a new spring constant. The spring constant \( k' \) of each part can be determined as follows: - The spring constant of a spring is inversely proportional to its length. When the original spring is cut into \( n \) parts, the length of each part is \( \frac{L}{n} \) (where \( L \) is the original length). - Therefore, the new spring constant \( k' \) for each part becomes: \[ k' = n \cdot k \] ### Step 3: Determine the New Time Period Now, we need to find the new time period \( T' \) for each part of the spring. Using the formula for the time period with the new spring constant: \[ T' = 2\pi \sqrt{\frac{m}{k'}} \] Substituting \( k' = n \cdot k \): \[ T' = 2\pi \sqrt{\frac{m}{n \cdot k}} \] ### Step 4: Relate the New Time Period to the Original Time Period We can express \( T' \) in terms of the original time period \( T \): \[ T' = 2\pi \sqrt{\frac{m}{k}} \cdot \frac{1}{\sqrt{n}} = T \cdot \frac{1}{\sqrt{n}} \] ### Conclusion Thus, the time period of each part of the spring after cutting it into \( n \) equal parts is: \[ T' = \frac{T}{\sqrt{n}} \]

To solve the problem, let's break it down step by step: ### Step 1: Understand the Time Period of a Spring The time period \( T \) of a spring in simple harmonic motion is given by the formula: \[ T = 2\pi \sqrt{\frac{m}{k}} \] where: ...
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