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A body executes simple harmonic motion. ...

A body executes simple harmonic motion. The potential energy (P.E), the kinetic energy (K.E) and energy (T.E) are measured as a function of displacement `x`. Which of the following staements is true?

A

(a) K.E. is maximum when `x=0`.

B

(b) T.E is zero when `x=0`

C

(c ) K.E is maximum when x is maximum

D

(d) P.E is maximum when `x=0`

Text Solution

Verified by Experts

The correct Answer is:
A

(a) `K.E.=1/21/2 momega^(2)(a^(2)-x^(2)`.
Where `x=0`, K.E is maximum and is equal to `1/2momega^(2)a^(2)`.
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