If x, and a denote the displacement, the velocity and the acceler of a particle executing simple harmonic motion of time period T, then, which of the following does not change with time?

Options

A. (a) `aT//x`
B. (b) `aT+2piv`
C. (c ) `aT//v`
D. (d) `a^(2)T^(2)+4pi^(2)v^(2)`

Answer

A

Explanation

(a) For an SHM, the acceleration `a=-omega^(2)x` where `omega^(2)` is a constant. Therefore `a/x` is a constant. The time period
(T) is also constant. Therfore `(aT)/x` is a constant.