Sound waves of frequency `660 Hz` fal normally on a perfectly reflecting wall. The shortest distance from the wall at which the pair particles have maximum amplitude of vibration is ……………… meters.

Answer

A, B

Explanation

`c = vlambda` : .lambda = ( c )/(v) = (330)/(660) = 0.5m`
the rarefaction will be at a distance of
`(lambda)/(4) = (0.5)/(4) = 0.125m`