The extension in a string, obeying Hooke's law, is x. The speed of sound in the stretched string is v. If the extension in the string is increased to `1.5 x`, the speed of sound will be :-

Options

A. `1.22v`
B. `0.61v`
C. `1.50v`
D. `0.75v`

Answer

A

Explanation

(a) Velocity of sound by a stretched string `v = sqrt((T)/(m))`
`(v)/(v') = sqrt((T)/(T'))` `v' = vsqrt((T')/(T)) = vsqrt((1.5x)/(x)) = 1.22v`