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A hollow pipe of length 0.8m is closed a...

A hollow pipe of length `0.8m` is closed at one end. At its open end a `0.5 m` long uniform string is vibrating in its second harmonic and it resonates with the fundamental frequency of the pipe. If the tension in the wire is `50 N` and the speed of sound is `320 ms^(-1)`, the mass of the string is

A

(a) `5 grams`

B

(b) `10 grams`

C

( c ) `20 grams`

D

(d) `40 grams`

Text Solution

Verified by Experts

The correct Answer is:
B

(b) Frequency of `2nd` harmonic of string = Fundamental frequency produced in the pipe

:. `2 xx [(1)/(2l_(1))sqrt((T)/(mu))] = (v)/(4l_(2)`
:. `(1)/(0.5)sqrt((50)/(mu)) = (320)/(4 xx 0.8)`
:. `mu = 0.02 kgm_(1)`
`The mass of the string = mul_(1)`
`= 0.02 xx 0.5kg = 10g`
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Knowledge Check

  • A string 2.0 m long and fixed at its end is driven by a 240 Hz vibrator. The string vibrates in its third harmonic mode. Speed of the wave and its fundamental frequency will be:

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