A wave equation which gives the displacement along the y-direction is given by `y = 10^(-4) sin(60t + 2x)` where `x and y` are in meters and `t` is time in secinds. This represents a wave

Options

A. (a) travelling with a velocity of `30m//s` in the nrgative x dierction
B. (b) of wavelength `pim`
C. ( c ) of frequency `30//pi hertz`
D. (d) of amplitude `10^(-4m` travelling along the negative x- direction

Answer

A, B, C, D

Explanation

(a,b,c,d) `y = 10^(-4)sin(60t - 2x)`
Comparing the given equation with the standered wave equation travelling in negative x-direction
`y = a sin (omegat + kx)`
we get amplitude `a = 1-^(-4)m`
Also, `omega = 60rad//s` :. `2pif = 60` rArr `f = (30)/(pi)Hz`
Also, `k = 2` rArr `(2pi)/(lambda) = 2` rArr `lambda = pim`
We know that `v = flambda = (30)/(pi) xx pi = 30m//s`