An air columbn in pipe, which is closed at one end, will be in resonance with a vibrating tuning fork of frequency `264 Hz` if the length of the column in `cm` is :

Options

A. (a) `31.25`
B. ( b) `62.50`
C. ( c ) `93.75`
D. (d) `125`

Answer

A, C

Explanation

(a,c) The wavelength possible in an air column in a pipe which has one closed end is
`lambda = (4l)/((2n + 1))` So, `c = vlambda`
`300 = 264 xx (4l)/(2n + 1)`
`v = 264 Hz` as it is in resonnance with a vibrating tuning fork of frequency `264 Hz`.
`l = (330 xx (2n +1))/(264 xx 4)`
For `n = 1`, `l = 0.3125m = 31.25cm`
For `n = 2`, `l = 0.9375m = 93.75cm`