A `20 cm` long string, having a mass of `1.0g`, is fixed at both the ends. The tension in the string is `0.5 N`. The string is into vibrations using an external vibrator of frequency `100 Hz`. Find the separation (in cm) between the successive nodes on the string.

Explanation

We know that, `v = sqrt((T)/(mu)) = sqrt((0.5)/(10^(-3)//0.2)) = 10m//s`
The wavelength of the wave established
`lambda = (v)/(f) = (10)/(100) = 0.1 m = 10m`
:. The distance between two successive nodes
`= (lambda)/(2) = (10)/(2) = 5cm`