On moving a charge of 20 coulomb by 2cm, 2J of work is done, then the potential difference between the points is

Options

A. (a) 0.1V
B. (b) 8V
C. (c) 2V
D. (d) 0.5V

Explanation

To find the potential difference between two points when a charge is moved, we can use the formula for work done in moving a charge in an electric field:

\[ W = Q \cdot V \]

Where:
- \( W \) is the work done (in joules),
- \( Q \) is the charge (in coulombs),
- \( V \) is the potential difference (in volts).

Given:
- Work done \( W = 2 \, \text{J} \)
- Charge \( Q = 20 \, \text{C} \)

We need to find the potential difference \( V \).

### Step 1: Rearrange the formula to find potential difference
We can rearrange the formula to solve for \( V \):

\[ V = \frac{W}{Q} \]

### Step 2: Substitute the values into the formula
Now, substitute the values of \( W \) and \( Q \) into the equation:

\[ V = \frac{2 \, \text{J}}{20 \, \text{C}} \]

### Step 3: Perform the calculation
Now, calculate the value:

\[ V = \frac{2}{20} = 0.1 \, \text{V} \]

### Conclusion
The potential difference between the two points is \( 0.1 \, \text{V} \).