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A parallel plate condenser with a dielec...

A parallel plate condenser with a dielectric of dielectric constant K between the plates has a capacity C and is charged to a potential V volt. The dielectric slab is slowly removed from between the plates and then reinserted. The net work done by the system in this process is

A

(a) zero

B

(b) `1/2(K-1)CV^2`

C

(c) `(CV^2(K-1))/(K)`

D

(d) `(K-1)CV^2`

Text Solution

Verified by Experts

The correct Answer is:
A
The potential energy of a charged capacitor before removing the dielectric slat is `U=(Q^2)/(2C)`.
The potential energy of the capacitor when the dielectric slat is first removed and the reinserted in the gap between the plates is `U=(Q^2)/(2C)`
There is no change in potential energy, therefore work done is zero.
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