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A parallel plate capacitor is made of tw...

A parallel plate capacitor is made of two circular plates separated by a distance 5mm and with a dielectric of dielectric constant 2.2 between them. When the electric field in the dielectric is `3xx10^4V//m` the charge density of the positive plate will be close to:

A

(a) `6xx10^-7C//m^2`

B

(b) `3xx10^-7C//m^2`

C

(c) `3xx10^4C//m^2`

D

(d) `6xx10^4C//m^2`

Text Solution

Verified by Experts

The correct Answer is:
A
Electric field in presence of dielectric between the two plates of a parallel plate capacitor is given by,
`E=(sigma)/(Kepsilon_0)`
Then, charge density
`sigma=Kepsilon_0E`
`=2.2xx8.85xx10^(-12)xx3xx10^4~~6xx10^-7C/m^2`
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