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In the circuit shown below, each battery...

In the circuit shown below, each battery is 5V and has an internal resistance of 0.2 ohm.

The reading in the ideal voltmeter V is .

Text Solution

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Let a current I flow through the circuit. Net emf of the circuit
`= 8(5V) = 40V`
Net resistance in the circuit `= 8(0.2 Omega) = 1.6Omega`
Current flowing through the circuit,
`I = (40 V)/(1.6Omega) = 25 A`
The voltmeter reading would be
`V = E-IR = (5V)-(25A)(0.2Omega)`
`=5V-5V = 0`.
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