In the circuit shown in fig the heat produced in the 5 ohm resistor due to the current flowing through it is 10 calories per second.

The heat generated in the 4 ohms resistor is

Options

A. `1cal//sec`
B. `2cal//sec`
C. `3cal//sec`
D. `4cal//sec`

Answer

B

Explanation

(b) Since `R_(AB) = 2R_(CD)` therefore, current in AB will be half as compared to current in CD.
`P_4/P_5 = ((i//2)^2 4)/(i^2 xx 5) = 1/5 rArr P_4 = 10/5 = 2cal//s`
Here `P_4 = power dissipation in 4Omega`
`P_5 = Power dissipation in 5Omega`.