The current I in the circuit is

Options

A. 1/45 A
B. 1/15 A
C. 1/10 A
D. 1/5 A

Answer

C

Explanation

(c) BC and AC are in series
`:. R_(BCA) = 30 + 30 = 60 Omega`
Now BA and DC are in parallel.
`1/R_(eq) = 1/30 + 1/60 = 90/(30 xx 60)`
`R_(eq) = 20Omega , V = IR`
`rArr I = 2/20 = 0.1 Amp. `